Lesson 1.4: More on Limits

Two of the functions we looked at in Lesson 2, h(x)=1/x^2 and k(x)=1/x, also have seemingly interesting behavior as x increases without bound. Upon looking at the graphs of y=h(x) and h(x)=y=k(x), it seems that y is getting very close to zero as x is getting very large. We can write this mathematically as lim(x->infinity)h(x)=lim(x->infinity)k(x)=0. It is also apparent that lim(x->-infinity)h(x)=lim(x->-infinity)k(x)=0.

Graph of y=f(x)=1/x^2
The graph of y=h(x)=1/x^2
Graph of y=f(x)=1/x
The graph of y=fk(x)=1/x

Let’s also consider f(x)=2-1/x and g(x)=tan(x). Upon looking at the graphs of y=f(x), we might conclude that lim(x->infinity)f(x)=lim(x->-infinity)f(x)=2. The graph of y=g(x) is a bit more interesting. Firstly, we note that the function’s ;limit is undefined at x=Pi/2. (Note that in calculus, we always measure angles in radians.) However, the limit from the right is -infinity and the limit from the left is infinity. Thus we must write lim(x->Pi/2+)g(x)=-infinity and lim(x->Pi/2-)g(x)=infinity. In fact, since tan(x) is periodic with period Pi, we can say lim(x->Pi/2+kPi+)g(x)=-infinity and lim(x->Pi/2+kPi-)g(x)=infinity for k an integer (i.e., k is an integer).

Graph of y=f(x)=2-1/x
The graph of y=f(x)=2-1/x
Graph of y=g(x)=tan(x)
The graph of y=g(x)=tan(x)

Valid XHTML 1.1!
Valid CSS!